16x^2-62x-45=0

Solution for 16x^2-62x-45=0 equation:

16x^2-62x-45=0

a = 16; b = -62; c = -45;
Δ = b2-4ac
Δ = -622-4·16·(-45)
Δ = 6724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6724}=82$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-82}{2*16}=\frac{-20}{32}
=-5/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+82}{2*16}=\frac{144}{32}
=4+1/2
$